Aug 12, 2015 · Given a cubic polynomial with real coefficients of the form f(x) = Ax3 + Bx2 + Cx + D (A ≠ 0) I am trying to determine what the necessary conditions of the coefficients are so that f(x) has …

For extracting the cubic roots we have also to choose a determination for the cubic roots, and this gives nine possible values for the first root of an equation which has only three roots. A correct solution …

Feb 6, 2021 · All of the examples on the internet I could find are made so that you can somehow make the cubic equation into a first degree polynomial multiplied by a second degree polynomial. But what …

In general, the discriminant of a polynomial is the product of the square of the differences of the roots. Hence, it is zero if and only if there is a multiple root.

Now for my questions: How far am I from solving the cubic polynomial problem myself without any external help? More over, I give up. How to find the roots of a cubic equation? Could my latest idea …

Sep 23, 2023 · How to find the remainder when a large degree polynomial is divided by a cubic polynomial with repeated roots. Ask Question Asked 2 years, 3 months ago Modified 2 years, 3 …

The formula provides a value for each of the 3 roots of the cubic equation. In your case, if you apply the formula you get $\left (x-3\right)\left (x+3.79134\right)\left (x-0.79134\right)$. The roots are accurate …

Jan 2, 2019 · In p(x) =x3 −x2 p (x) = x 3 x 2, both 0 0 and 1 1 are possible roots of the polynomial; both are real. I had read that a cubic polynomial has either all real roots or just one real root. It can't have …

Mar 26, 2023 · First of all I wanted to clarify that this is my first post here. I was trying to find a solution to the general depressed cubic polynomial and was able to get to the right formula but there are some

16 While they do start getting awkward quickly, the next few ordinals are fairly well-defined, largely because of their occasional usage in solving cubic and quartic equations and in defining algebraic …