Apr 29, 2019 · Since the sequence is geometric with ratio r r, a2 = ra1,a3 = ra2 = r2a1, a 2 = r a 1, a 3 = r a 2 = r 2 a 1, and so on. With this fact, you can conclude a relation between a4 a 4 and a1 a 1 in …

Nov 25, 2020 · The only given values are the sum of an infinite geometric series which is equal to 9/2, and the second term which is equal to -2. How do I find the common ratio here?

Given: Geometric Series Sum (Sn S n) = 39 First Term (a1 a 1) = 3 number of terms (n n) = 3 Find the common ratio r r. *I have been made aware that the the common ratio is 3, but for anyone trying to …

Aug 9, 2020 · 5 There is a question in my book stating that A geometric progression consists of an even number of terms. If the sum of all the terms is five times the sum of terms occupying odd places then …

Find the common ratio, if the sum of first 8 terms in GP (geometric progression) is 5 times the sum of first 4 terms also in GP. Ask Question Asked 11 years, 5 months ago Modified 11 years, 5 months ago

Aug 19, 2020 · Find the first term and the common ratio of an infinite geometric series whose sum is $5$ and such that each term is $4$ times the sum of all the terms that follow it.

Jan 15, 2018 · The fact that you're asking for a common ratio probably means that the sequence with terms $b_n$ form a geometric sequence but that's something you should mention.

Dec 8, 2014 · Thanks for your help. I marked your answer as best because your explaination of "multiplying by one more x^7" for finding the common ratio really clarified this problem for me. I found …

Jul 8, 2015 · Given a geometric sequence where the 5 5 th term = 162 = 162 and the 8 8 th term = −4374 = 4374, determine the first three terms of the sequence. I am unclear how to do this without …

Feb 14, 2018 · I need to clarify if the way of working out is correct for finding the common ratio, given the first term of a geometric series and its sum to infinity. First term: a = 8 Given Sum: S = 400 Ratio: ...